List of top Mathematics Questions on Random Variables and its Probability Distributions asked in KCET

A random variable $X$ has the following probability distribution: \[ \begin{array}{|c|c|c|c|} \hline X & 0 & 1 & 2 \\ \hline P(X) & \frac{25}{36} & k & \frac{1}{36} \\ \hline \end{array} \] If the mean of the random variable $X$ is $\frac{1}{3}$, then the variance is:
A random variable X has the following probability distribution:
\(X\)012
\(P(X)\)\(\frac{25}{36}\)k\(\frac{1}{36}\)
If the mean of the random variable X is \(\frac{1}{3}\), then the variance is