List of top Physics Questions on Projectile motion asked in Haryana PMT

The formula for horizontal range of a projectile is $S=\frac{v^{2}\sin ^{2}\theta }{2g}$ where $v$ is initial speed, $ \theta $ angle of inclination and $g$ is acceleration due to gravity. The Wheatstone bridge shown in figure can be used to determine the range if the following arrangement is made

A heavy stone hanging from a massless string of length $15\, m$ is projected horizontally with speed $147\, m/ s$. The speed of the particle at the point where the tension in the string equals the weight of the particle is?

An object is thrown along a direction making an angle $45^{\circ}$ with the horizontal direction. The horizontal range of the object is equal to :