In a semiconductor, the ratio of electronic mobility to hole mobility is 10. The density of electrons and holes are $10^{15}$ m$^{-3}$ and $10^{16}$ m$^{-3}$, respectively. If the conductivity is $1.6 \ \Omega^{-1}$ m$^{-1}$, then the mobility of holes is $________________ \ (m^2 V^{-1} s^{-1})$.
Given: $q = 1.6 \times 10^{-19}$ C
