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List of top Mathematics Questions on Statistics asked in BITSAT
Find the mean deviation about the mean for the data:
\( 4, 7, 8, 9, 10, 12, 13, 17 \)
BITSAT - 2023
BITSAT
Mathematics
Statistics
The marks obtained by 60 students in a certain test are given below:
Marks: 10–20, 20–30, 30–40, 40–50, 50–60, 60–70, 70–80, 80–90, 90–100
No. of students: 2, 3, 4, 5, 6, 12, 14, 10, 4
Median of the above data is
BITSAT - 2021
BITSAT
Mathematics
Statistics
The arithmetic mean of numbers a,b,c,d,e is M. What is the value of
(a-M)+(b-M)+(c-M)+(d-M)+(e-M)?
BITSAT - 2020
BITSAT
Mathematics
Statistics
The arithmetic mean of the data 0,1,2,…,n with frequencies 1,1,1,…,1 is
BITSAT - 2019
BITSAT
Mathematics
Statistics
The average age of 8 men is increased by 2 years when one of them whose age is 20 yr is replaced by a new man. What is the age of the new man?
BITSAT - 2019
BITSAT
Mathematics
Statistics
In a frequency distribution, the mean and median are 21 and 22 respectively. Then its mode is approximately:
BITSAT - 2018
BITSAT
Mathematics
Statistics
The marks obtained by 60 students are given. The median of the data is
BITSAT - 2017
BITSAT
Mathematics
Statistics
The arithmetic mean of numbers a, b, c, d, e is M. What is the value of (a-M)+(b-M)+(c-M)+(d-M)+(e-M)?
BITSAT - 2016
BITSAT
Mathematics
Statistics
The average age of 8 men is increased by 2 years when one of them whose age is 20 years is replaced by a new man. What is the age of the new man?
BITSAT - 2015
BITSAT
Mathematics
Statistics
The arithmetic mean of the data \(0,1,2,\ldots,n\) with frequencies \(1,{}^nC_1,{}^nC_2,\ldots,{}^nC_n\) is
BITSAT - 2015
BITSAT
Mathematics
Statistics
The arithmetic mean of the data
$0,1,2, \ldots \ldots, n$
with frequencies
$1,{ }^{n} C_{1},{ }^{n} C_{2}, \ldots,{ }^{n} C_{n}$
is
BITSAT - 2015
BITSAT
Mathematics
Statistics
If the value of mode and mean is 60 and 66 respectively, then the value of median is
BITSAT - 2013
BITSAT
Mathematics
Statistics
Mean of 25 observations was found to be 78.4. But later it was found that 96 was misread as 69. The correct mean is
BITSAT - 2010
BITSAT
Mathematics
Statistics
If the mean, mode and S.D. of a frequency distribution are 41.45 and 8 respectively, then its Pearson’s coefficient of skewness is
BITSAT - 2010
BITSAT
Mathematics
Statistics
Mean of $25$ observations was found to be $78.4$. But later on it was found that $96$ was misread $69$. The correct mean is
BITSAT - 2010
BITSAT
Mathematics
Statistics