List of top Mathematics Questions on Plane asked in BITSAT

The equation of a plane passing through three non-collinear points is determined using:

Let the foot of perpendicular from a point \( P(1,2,-1) \) to the straight line \( L : \frac{x}{1} = \frac{y}{0} = \frac{z}{-1} \) be \( N \). Let a line be drawn from \( P \) parallel to the plane \( x + y + 2z = 0 \) which meets \( L \) at point \( Q \). If \( \alpha \) is the acute angle between the lines \( PN \) and \( PQ \), then \( \cos \alpha \) is equal to:

Let the acute angle bisector of the two planes \( x - 2y - 2z + 1 = 0 \) and \( 2x - 3y - 6z + 1 = 0 \) be the plane \( P \). Then which of the following points lies on \( P \)?

Let R be the relation "is congruent to" on the set of all triangles in a plane. Is R:

Find the coordinates of the point where the line joining the points \( (2, -3, 1) \) and \( (3, -4, -5) \) cuts the plane \( 2x + y + z = 7 \):

The equation of the plane containing the line x-x₁=y-y₁m=z-z₁n is a(x-x₁)+b(y-y₁)+c(z-z₁)=0, then

The equation of plane passing through a point $A (2,-1,3)$ and parallel to the vectors $a =(3,0,-1)$ and $b =(-3,2,2)$ is:

The point of intersection of the line $\frac{x-1}{3}=\frac{y+2}{4}=\frac{z-3}{-2}$ and plane $2 x-y+3 z-1= 0$ is.