\(P(A) = \frac{1}{3}\), \(P(B) = \frac{3}{4}, P(A \cap B) = \frac{1}{6}\), then probability of \( A \) alone is
If \( A \) and \( B \) are two events such that \(P(A \cap B) = \frac{1}{3}\), \(P(A \cup B) = \frac{5}{6}\), and \(P(B) = \frac{1}{2}\), then the events are:
If $p = \frac{1}{8}; n = 640; q = \frac{7}{8}$, then variance Binomial Distribution