List of top Physics Questions on Projectile motion asked in AP EAMCET

In a sport event a disc is thrown such that it reaches its maximum range of 80 m, the distance travelled in first 3 s is (g = 10ms\(^2\))
A ball is projected at an angle of \( 45^\circ \) with the horizontal. It passes through a wall of height \( h \) at a horizontal distance \( d_1 \) from the point of projection and strikes the ground at a distance \( d_1 + d_2 \) from the point of projection, then \( h \) is:
Path of projectile is given by the equation \( Y = Px - Qx^2 \), match the following accordingly (acceleration due to gravity = \( g \))
Path of projectile is given by the equation Y = Px−Qx2
A 2 kg ball is thrown vertically upward and another 3 kg ball is projected with a certain angle (\( \theta \neq 90^\circ \)). Both will have the same time of flight. The ratio of their maximum heights is:
A bowling machine placed at a height \( h \) above the earth surface releases different balls with different angles but with the same velocity \( 10 \sqrt{3} \, \text{ms}^{-1} \). All these balls landing velocities make angles 30° or more with horizontal. Then the height \( h \) (in meters) is:
A boy throws a ball with a velocity \(V_0\) at an angle \(\alpha\) to the ground. At the same time, he starts running with uniform velocity to catch the ball before it hits the ground. To achieve this, he should run with a velocity of:
A boy weighing 50 kg finished a long jump at a distance of 8 m. Considering that he moved along a parabolic path and his angle of jump is \( 45^\circ \), his initial kinetic energy is:

Match the following physical quantities with their respective dimensional formulas.

An object is projected such that it has to attain maximum range, while another body is projected to reach maximum height. If both objects reached the same maximum height, then find the ratio of their initial velocities.
One second after projection, a projectile is travelling in a direction inclined at \( 45^\circ \) to horizontal. After two more seconds it is travelling horizontally. Then the magnitude of velocity of the projectile is ( \( g = 10 \) ms\(^{-2}\)):
A ball at point ‘O’ is at a horizontal distance of 7 m from a wall. On the wall, a target is set at point ‘C’. If the ball is thrown from ‘O’ at an angle \( 37^\circ \) with horizontal aiming the target ‘C’. But it hits the wall at point ‘D’ which is a vertical distance \( y_0 \) below ‘C’. If the initial velocity of the ball is 15 m/s, find \( y_0 \). (Given \( \cos 37^\circ = \frac{4}{5} \))
A ball at point ‘O’ is at a horizontal distance

The percentage error in the measurement of mass and velocity are 3% and 4% respectively. The percentage error in the measurement of kinetic energy is:

A car travelling at 80 kmph can be stopped at a distance of 60 m by applying brakes. If the same car travels at 160 kmph and the same braking force is applied, the stopping distance is:
A body thrown vertically upwards reaches a maximum height \( H \). The ratio of the velocities of the body at heights \( \frac{3H}{4} \) and \( \frac{8H}{9} \) from the ground is:
The equation of projectile motion is given by \( y = 3x - 0.8x^2 \). The time of flight of the projectile is (Acceleration due to gravity \( g = 10 \) m/s²):
A projectile with speed \(50\ \text{m s}^{-1}\) is thrown at an angle of \(60^\circ\) with the horizontal. The maximum height that can be reached is
\[ \text{Acceleration due to gravity}=10\ \text{m s}^{-2} \]