List of top Physics Questions on simple harmonic motion asked in AP EAMCET

The displacement of a particle executing SHM is given by $ X = 0.01 \sin 100\pi (t + 0.05) $. The time period of the particle is:

A body is executing simple harmonic motion. At a displacement $ x $, its potential energy is $ E_1 $, and at a displacement $ y $, its potential energy is $ E_2 $. The potential energy $ E $ at a displacement $ (x + y) $ is:

The displacement of a particle of mass $2g$ executing simple harmonic motion is \[ x = 8 \cos \left( 50t + \frac{\pi}{12} \right) \text{ m}, \] where $t$ is time in seconds. The maximum kinetic energy of the particle is:

The displacement of a particle executing simple harmonic motion is $ y = A \sin(2\pi t + \phi) \, \text{m} $, where $ t $ is time in seconds and $ \phi $ is the phase angle. At time $ t = 0 $, the displacement and velocity of the particle are 2 m and 4 ms^-1. The phase angle, $ \phi $ =

As shown in the figure, two blocks of masses $m_1$ and $m_2$ are connected to a spring of force constant $k$. The blocks are slightly displaced in opposite directions to $x_1, x_2$ distances and released. If the system executes simple harmonic motion, then the frequency of oscillation of the system ($\omega$) is:

A mass $ M $, attached to a horizontal spring executes simple harmonic motion with amplitude $ A_1 $. When mass $ M $ passes mean position, then a smaller mass $ m $ is attached to it, and both of them together execute simple harmonic motion with amplitude $ A_2 $. Then the value of $ \frac{A_1}{A_2} $ is:

Time period of a simple pendulum in air is $ T $. If the pendulum is in water and executes SHM, its time period is $ t $. The value of $ \frac{T}{t} $ is [Density of bob is $ \frac{5000}{3} $ kg/m$^3$]

A pan with a set of weights attached to a light spring oscillates with a time period of 0.6 s. When an additional weight is added, the time period becomes 0.7 s. The extension due to the additional weight is:

The displacement of a particle varies with time as $ x = 4 \sin 3\omega t $. If its motion is simple harmonic, then its maximum acceleration is:

For a particle executing simple harmonic motion, match the following statements (conditions) from column I to statements (shapes of graph) in column II.

The displacement of a damped oscillator is $ x(t) = \exp(-0.2t) \cos(3.2t + \phi) $, where $ t $ is time in seconds. The time required for the amplitude of the oscillator to become $ \frac{1}{e^{1.2}} $ times its initial amplitude is

The relation between the force (F in newton) acting on a particle executing simple harmonic motion and the displacement of the particle (y in metre) is given by: \[ 500F + \pi^2 y = 0 \] If the mass of the particle is 2 g, the time period of oscillation of the particle is:

For a particle executing simple harmonic motion, the displacement-time $(x - t)$ graph is as shown in the figure. The acceleration of the particle at $t = \frac{4}{3} s$ is