List of top Physics Questions on Moving charges and magnetism asked in AIIMS

Find force per unit length at P.
A semicircular arc of radius r and a straight wire along the diameter, both are carrying same current i. Find out magnetic force per unit length at point P.
A long straight wire carries 10 $A \,d.c$. current an electron travels perpendicular to the plane of this wire at a distance $0.1\, m$ with velocity $5.0 \times10^6 m \,s^{-1}$. Force acting on the electron due to current in wire is
A particle of charge q and mass m starts moving from the origin under the action of an electric field $\vec{E}=E_{0} \hat{i} $and $\vec{B}=B_{0} \hat{i}$ with a velocity $\vec{v}=v_{0} \hat{j}$ . The speed of the particle will become $\frac{\sqrt{5}}{2}v_{0}$ after a time
A charge, whether stationary or in motion produces a magnetic field around it. Moving charges produce only electric field in the surrounding space.
Voltmeter is connected in parallel with the circuit Resistance of a voltmeter is very large.
Circular loop of a wire and a long straight wire carry currents $I _{ c }$ and $I _{ e }$, respectively as shown in figure. Assuming that these are placed in the same plane. The magnetic field will be zero at the centre of the loop when the separation $H$ is :
The magnetic moment of a current $(I)$ carrying circular coil of radius $(r)$ and number of turns $(n)$ varies as
A circular coil of radius $R$ carries an electric current. The magnetic field due to the coil at a point on the axis of the coil located at a distance $r$ from the center of the coil, such that $r > > R$, varies as
A wire of length $l$ carries a steady current. It is bent first to form a circular plane loop of one turn. The magnetic field at the centre of the loop is $B$. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same is
What should be the amount of current through the ring of radius $5\, cm$ so that field in the centre is with earth?s magnetic field of $7 \times 10^{-9} \,Wb/m^2$ is
A galvanometer can be changed into ammeter by providing