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Which one of the following compounds is a peroxide?
Which one of the following compounds is a peroxide?
Updated On: Jul 12, 2022
- $BaO_2$
- $MnO_2$
- $NO_2$
- $KO_2$
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The Correct Option is A
Solution and Explanation
In peroxide the oxidation number of $0$ is $-1$ and they give $H_2O_2$ with dilute acids and have peroxide linkage.
In $KO_2$ let O.S. of $O = x$
$\therefore$ $1 + (x \times 2) = 0 $
$\therefore = 1/2$ (It is a superoxide, not a peroxide).
In $BaO_2$, let $O.S.$ of $O = x$
$2 + (x \times 2) = 0$
$\therefore \, x = - 1 $(It is a peroxide)
In $MnO_2$ and $NO_2$, $Mn$ and $N$ exhibit variable oxidation states, the oxidation state of $0$ in these oxides is $-2$ and hence they are not peroxides. Among then only $BaO_2$ is a peroxide.
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Concepts Used:
Group 1 Elements
Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.
Alkali metals are characterized by one s-electron in the valence shell of their atoms.
Alkali metals have a corresponding [Noble gas] ns1 electronic configuration. They occupy the first column of the periodic table. Alkali elements are:
- Lithium(Li)
- Sodium(Na)
- Potassium (K)
- Rubidium (Ru)
- Cesium (Cs)
- Francium (Fr)
They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.
Electronic Configuration:
- Alkali metals have one electron in their valence shell.
- The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
- They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).
This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.
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