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Sum of First n Terms of an AP
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the sum of first 10 terms of the arithmetic progre
Question:
The sum of first 10 terms of the arithmetic progression 34, 32, 30, .….. is
AP POLYCET - 2024
AP POLYCET
Updated On:
May 7, 2024
200
225
250
275
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The Correct Option is
C
Solution and Explanation
The correct option is (C): 250.
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Top Questions on Sum of First n Terms of an AP
Let the first term of a series be \( T_1 = 6 \) and its \( r^\text{th} \) term \( T_r = 3T_{r-1} + 6^r \), \( r = 2, 3, \dots, n \). If the sum of the first \( n \) terms of this series is \[ \frac{1}{5} \left(n^2 - 12n + 39\right) \left(4 \cdot 6^n - 5 \cdot 3^n + 1\right), \] then \( n \) is equal to ______.
JEE Main - 2024
Mathematics
Sum of First n Terms of an AP
View Solution
\[\lim_{n \to \infty} \frac{(1^2 - 1)(n-1) + (2^2 - 2)(n-2) + \ldots + ((n-1)^2 - (n-1))}{(1^3 + 2^3 + \ldots + n^3) - (1^2 + 2^2 + \ldots + n^2)}\]is equal to:
JEE Main - 2024
Mathematics
Sum of First n Terms of an AP
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Let \( S_n \) denote the sum of the first \( n \) terms of an arithmetic progression. If \( S_{20} = 790 \) and \( S_{10} = 145 \), then \( S_{15} - S_5 \) is:
JEE Main - 2024
Mathematics
Sum of First n Terms of an AP
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If
\(S_n=3+7+11....\)
upto
\(n\)
terms and
\(40<\frac {6}{n(n+1)}\displaystyle\sum_{k=1}^n S_k<45\)
. Then
\(n\)
is
JEE Main - 2024
Mathematics
Sum of First n Terms of an AP
View Solution
Let
\(a_1,a_2,a_3\)
, ..., an, be in A. P. and
\(S_n\)
denotes the sum of first
\(n\)
terms of this A. P. is
\(S_{10}\)
=
\(390, \frac{a_{10}}{a_{50}} =\frac{15}{7}\)
, then
\(S_{15} -S_5 =\)
_________.
JEE Main - 2024
Mathematics
Sum of First n Terms of an AP
View Solution
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