Question:

The ratio of radii of gyration of a circular ring and a circular disc, of the same mass and radius, about an axis passing through their centres and perpendicular to their planes are :

Updated On: Jul 13, 2024
  • $ 1: \sqrt 2 $
  • 3 : 2
  • 2 : 1
  • $ \sqrt 2 :1 $
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The Correct Option is D

Solution and Explanation

Let M and R be mass and radius of the ring and the disc respectively. Then,
Moment of inertia of ring about an axis passing
through its centre and perpendicular to its plane is
$ I_{ring} = MR^2 $
Moment of inertia of disc about the same axis is
$ I_{disc} = \frac{MR^2}{2} $
As $ I = MK^2 $ where k is the radius of gyration
$ \therefore I_{ring} = MK^2_{ring} = MR^2 $
or $ k_{ring} = R $
and $ I_{disc} = Mk^2_{disc} = \frac{MR^2}{2} $
or $ k_{disc} = \frac{R}{\sqrt 2} $
$ \therefore \frac{k_{ring}}{k_{disc}} = \frac{R}{R/ \sqrt 2} = \frac{\sqrt 2}{1} $
$ k_{ring} : k_{disc} = \sqrt 2 :1 $
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Concepts Used:

Moment of Inertia

Moment of inertia is defined as the quantity expressed by the body resisting angular acceleration which is the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

Moment of inertia mainly depends on the following three factors:

  1. The density of the material
  2. Shape and size of the body
  3. Axis of rotation

Formula:

In general form, the moment of inertia can be expressed as, 

I = m × r²

Where, 

I = Moment of inertia. 

m = sum of the product of the mass. 

r = distance from the axis of the rotation. 

M¹ L² T° is the dimensional formula of the moment of inertia. 

The equation for moment of inertia is given by,

I = I = ∑mi ri²

Methods to calculate Moment of Inertia:

To calculate the moment of inertia, we use two important theorems-

  • Perpendicular axis theorem
  • Parallel axis theorem