Question:

The radius of fifth orbit of the Li++ is __________ × 10^-12 m.
Take : radius of hydrogen atom = 0.51 Å

Updated On: Mar 4, 2024
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Correct Answer: 425

Solution and Explanation

\(𝑟_𝑛 = \frac{0.51𝑛^2}{𝑍} 𝐴_0 \)
For Li++, z=3.
So \(𝑟_5 = 0.51 × \frac{25}{3} × 10^{−10}\) 𝑚 = 17 × 25 × \(10^{−12}𝑚\) = 425 × \(10^{−12}\)m
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