Question:

The displacement of a charge $Q$ in the electric field $E=e_{1} 1+e_{2} j+e_{3} k$ is $r=a i+b j$. The work done is

Updated On: Jun 18, 2022
  • $Q (ae_1 + be_2)$
  • $Q \, \overline {{ae_1 } ^2 + {be_2 }^2}$
  • $Q(e_1 + e_2)\,\, \overline{a^2 + b^2}$
  • $Q \overline{e_1^2 + e_2^2} \,\,a + b$
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The Correct Option is A

Solution and Explanation

By using $W = Q ( E \Delta r )$
$\Rightarrow W=Q\left[\left(e_{1}\, l+e_{2}\, j+e 3 \,k\right) \cdot(a i+b j)\right]$
$=Q\left(e_{1} a+e_{2} b\right)$
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Concepts Used:

Electric Field

Electric Field is the electric force experienced by a unit charge. 

The electric force is calculated using the coulomb's law, whose formula is:

\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)

While substituting q2 as 1, electric field becomes:

 \(E=k\dfrac{|q_{1}|}{r^{2}}\)

SI unit of Electric Field is V/m (Volt per meter).