Question:

The coefficient of $x^{20}$ in the expansion of $(1 + x^2)^{40} . (x^2 + 2 + \frac{1}{x^2})^{-5}$ is

Updated On: Jun 18, 2022
  • $^{30}C_{10}$
  • $^{30}C_{25}$
  • $1$
  • None of these
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The Correct Option is B

Solution and Explanation

Expression = $= \left(1+x^{2}\right)^{40} .\left(x+\frac{1}{x}\right)^{-10} $
$ =\left(1+x^{2}\right)^{30} .x^{10} $
The coefficient of $x^{20} $ in $x^{10}\left(1+x^{2}\right)^{30} $
$=$ the coefficient of $ x^{10} $ in $\left(1+x^{2}\right)^{30} $
$ = \,^{30} C_{5} =\,^{30}C_{30-5} = \,^{30}C_{25} $
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Concepts Used:

Binomial Expansion Formula

The binomial expansion formula involves binomial coefficients which are of the form 

(n/k)(or) nCk and it is calculated using the formula, nCk =n! / [(n - k)! k!]. The binomial expansion formula is also known as the binomial theorem. Here are the binomial expansion formulas.

This binomial expansion formula gives the expansion of (x + y)n where 'n' is a natural number. The expansion of (x + y)n has (n + 1) terms. This formula says:

We have (x + y)n = nC0 xn + nC1 xn-1 . y + nC2 xn-2 . y2 + … + nCn yn

General Term = Tr+1 = nCr xn-r . yr

  • General Term in (1 + x)n is nCr xr
  • In the binomial expansion of (x + y)n , the rth term from end is (n – r + 2)th .