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Question:
Reaction of ethyl formate with excess of ${CH_3Mgl}$ followed by hydrolysis gives
Reaction of ethyl formate with excess of ${CH_3Mgl}$ followed by hydrolysis gives
Updated On: Jun 7, 2022
- $n$-propyl alcohol
- isopropyl alcohol
- acetaldehyde
- acetone.
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The Correct Option is B
Solution and Explanation
Secondary alcohol is obtained by reaction of ethyl formate with an excess of Grignard reagent followed by hydrolysis
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Concepts Used:
Preparation
Preparation of Aldehydes:
- In the presence of palladium catalyst spread on barium sulfate, Acid chlorides are reduced to aldehydes with hydrogen .
- This is known as Rosenmund reduction. It is mostly used for the preparation of aromatic aldehydes.
Preparation of Ketones:
- Acid chlorides on reaction with dialkyl cadmium form ketones. Grignard reagents are used in the preparation of Dialkyl cadmium.
- 2R-Mg-X + CdCl2 → R2Cd + 2 Mg(X)Cl
- 2RCOCl + R2Cd → 2R-CO-R + CdCl2
- The mixed ketones are prepared very conveniently.
Preparation of Carboxylic Acids:
- Primary alcohols are readily oxidized to carboxylic acids with common oxidizing agents such as potassium permanganate in neutral acidic or alkaline media or by potassium dichromate and chromium trioxide in acidic media.
- RCH2OH → RCOOH
- CH3(CH2)8CH2OH → CH3(CH2)8COOH
Read More: Aldehydes, Ketone, and Carboxylic Acids
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