Question

Products (X and Y) of the following reactions (I and II) are : I. $ \underset{\text{(Cold and dil.)}}{{2NaOH}}+ Cl_{2} \to Nacl+X+H_{2}O $ II. $ \underset{\text{(Hot and cone.)}}{{6NaOH}}+ 3Cl_{2} \to Nacl+Y+3H_{2}O $

• A. $ X = NaCIO_{3} $ and $ Y =NaOCI $
• B. $ X =NaCIO $ and $ V =NaOCI_{3} $
• C. $ X =NaHCIO_{3} $ and $ Y =NaOCI $
• D. $ X = NaCIO_{3} $ and $ Y = NaHCIO_{3} $

Answer 1

The Correct Option is B

Chlorine with cold and dilute alkali, $NaOH$ forms a mixture of chloride and hypochlorite as
$Cl_{2}+2NaOH(dil) { ->[Cold] } NaCl+\underset{\text{Sodium hypochlorite ( X)}}{{NaOCl+H_{2}O}}$
Chlorine with hot and concentrated alkali, $NaOH$ forms a mixture of chloride and chlorate as
$3Cl_{2}+3NaOH(conc.) { ->[Hot] } 5NaCl+\underset{\text{Sodium chlorate ( Y)}}{{NaClO_{3}+3H_{2}O}}$