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Moment of inertia of ring about its diameter is $ I $ Then, moment of inertia about an axis passing through centre perpendicular to its plane is
Moment of inertia of ring about its diameter is $ I $ Then, moment of inertia about an axis passing through centre perpendicular to its plane is
Updated On: Nov 11, 2023
- $ 2I $
- $ \frac{I}{2} $
- $ \frac{3}{2}I $
- $ I $
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The Correct Option is A
Solution and Explanation
By the theorem of perpendicular axes, the moment of inertia about the central axis $ I_{C} $ , will be equal to the sum of its moments of inertia about two mutually perpendicular diameters lying in its plane.
Thus, $I_{d}=I=\frac{1}{2} M R^{2}$
$\therefore I_{C}=I+I$
$=\frac{1}{2} M R^{2}+\frac{1}{2} M R^{2}$
$=I+I=2 I$
Thus, $I_{d}=I=\frac{1}{2} M R^{2}$
$\therefore I_{C}=I+I$
$=\frac{1}{2} M R^{2}+\frac{1}{2} M R^{2}$
$=I+I=2 I$
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Concepts Used:
Moment of Inertia
Moment of inertia is defined as the quantity expressed by the body resisting angular acceleration which is the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.
Moment of inertia mainly depends on the following three factors:
- The density of the material
- Shape and size of the body
- Axis of rotation
Formula:
In general form, the moment of inertia can be expressed as,
I = m × r²
Where,
I = Moment of inertia.
m = sum of the product of the mass.
r = distance from the axis of the rotation.
M¹ L² T° is the dimensional formula of the moment of inertia.
The equation for moment of inertia is given by,
I = I = ∑mi ri²
Methods to calculate Moment of Inertia:
To calculate the moment of inertia, we use two important theorems-
- Perpendicular axis theorem
- Parallel axis theorem
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