In $n$-type semiconductors electrons are majority carriers and holes are minority carriers.
$n_{e}=8 \times 10^{18} / m ^{3},$
$n_{h}=5 \times 10^{18} / m ^{3}, $
$\mu_{e}=2.3 \,m ^{2} / V - s , $
$\mu_{h}=0.01\, m ^{2} / V - s .$
As $n_{ e } > n_{h}$, so semiconductor is $n$-type.
Also conductivity $(\sigma)=\frac{1}{\text { Resistivity }(\rho)}$
$=e\left(n_{e} \mu_{e}+n_{h} \mu_{h}\right)$
$\Rightarrow \rho=1.6 \times 10^{-19}$
$\left[8 \times 10^{18} \times 2.3+5 \times 10^{18} \times 0.01\right]$
$\Rightarrow =0.34\, \Omega - m$