Question:

In a 3.2 Kbp long piece of DNA, 820 adenine bases were found. What would be the number of cytosine bases?

Updated On: Mar 5, 2024
  • 780
  • 1560
  • 740
  • 1480
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The Correct Option is A

Solution and Explanation

One Kbp of DNA contains 1000 base pairs. So the total number of base pairs in $3.2 kbp$ is (3.2X1000) $3200 bp$. Out of which 820 base pairs are adenine so the number of thymine will also be 820 as number of adenine is equal to thymine according to chargoffs rule. A total number of cytosine $+$ guanosine will be $3200-780 X 2=1560$. As the number of cytosine is equal to guanine so cytosine bases in the DNA can be calculated as $1560 / 2=780$.
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Concepts Used:

The Molecular Basis of Inheritance

DNA Replication:

DNA synthesis is commenced at particular points within the DNA strand referred to as ‘origins’, which are certain coding regions. There are numerous origin sites, and when replication of DNA starts, these sites are mentioned as replication forks. Within the replication, the complex is the enzyme DNA Helicase, so that they can be utilized as a template for replication. DNA Primase is another enzyme that's essential in DNA replication.

RNA:

Ribonucleic acid (RNA) is an essential biological macromolecule that exists all together in biological cells. It is principally involved in the synthesis of proteins, that carry the messenger instructions from DNA, which itself contains the genetic instructions needed for the event and maintenance of life. In some viruses, RNA, in spite of DNA, carries genetic information.

Genetic Code:

Genetic code is the term we use in the manner that the four bases of DNA--the A, C, G, and Ts--are strung together in a way that the ribosome, the cellular machinery, can read them and switch them into a protein. In the ordering, every three nucleotides during a row count as a triplet and code for one amino alkanoic acid.

Read More: Molecular Basis of Inheritance