Question

Find the product of the following pairs of monomials.
(i) 4, 7p
(ii) – 4p, 7p
(iii) – 4p, 7pq
(iv) 4p³, – 3p
(v) 4p, 0

Answer 1

(i) 4 , 7 p = 4 × 7 × p = 28p
(ii) – 4p × 7p = (-4 × 7 ) × (p × p )= -28p²
(iii) – 4p × 7pq =(-4 × 7 ) (p × pq) = -28p²q
(iv) 4p³ × – 3p = (4 × -3 ) (p³ × p ) = -12p⁴
(v) 4p × 0 = 0