Question:

Find the mean number of heads in three tosses of fair coin:

Updated On: Apr 20, 2024
  • 1.5
  • 2.5
  • 4.5
  • 3.5
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The Correct Option is A

Solution and Explanation

In three tosses of a fair coin, we have a total of \(2^3 = 8\) possible outcomes. 
These outcomes are: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT 
Counting the number of heads in each outcome, we have: 
HHH: 3 heads 
HHT: 2 heads 
HTH: 2 heads 
HTT: 1 head 
THH: 2 heads 
THT: 1 head 
TTH: 1 head 
TTT: 0 heads 
To find the mean, we sum up the number of heads in each outcome and divide by the total number of outcomes: 
\(\frac{{3 + 2 + 2 + 1 + 2 + 1 + 1 + 0}}{8} = \frac{12}{8} = 1.5\)
 Therefore, the mean number of heads in three tosses of a fair coin is 1.5. The correct option is (1) 1.5.

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