Find the kinetic energy of the fastest emitted electron if an ultraviolet ray of 6.2 falls on the aluminum surface, the work function given is 4.2 eV
Solution and Explanation
Kinetic Energy = Energy of Incident Photon - Work Function
Given:
The energy of Incident Photon = 6.2 eV
Work Function of Aluminum = 4.2 eV
Substituting these values into the equation, we have:
Kinetic Energy = 6.2 eV - 4.2 eV
Calculating the difference, we get:
Kinetic Energy = 2.0 eV
Therefore, the kinetic energy of the fastest emitted electron is 2.0 electron volts (eV).
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Concepts Used:
Dual Nature of Radiation and Matter
The dual nature of matter and the dual nature of radiation were throughgoing concepts of physics. At the beginning of the 20th century, scientists untangled one of the best-kept secrets of nature – the wave-particle duplexity or the dual nature of matter and radiation.
Electronic Emission
The least energy that is needed to emit an electron from the surface of a metal can be supplied to the loose electrons.
Photoelectric Effect
The photoelectric effect is a phenomenon that involves electrons getting away from the surface of materials.
Heisenberg’s Uncertainty Principle
Heisenberg’s Uncertainty Principle states that both the momentum and position of a particle cannot be determined simultaneously.
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