Question:

A metal wire of length $ l $ area of cross-section A and Young's modulus Y behaves as a spring of spring constant k given by

Updated On: Apr 7, 2024
  • $ k=\frac{YA}{l} $
  • $ k=\frac{2YA}{l} $
  • $ k=\frac{YA}{2l} $
  • $ k=\frac{Yl}{A} $
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The Correct Option is A

Solution and Explanation

$ Y=\frac{F/A}{\Delta l/l} $ $ \Rightarrow $ $ F=YA\frac{\Delta l}{l} $ ...(i) If $ k $ is spring constant, $ F=k\Delta l $ ... (ii) Comparing Eqs. (i) and (ii), we get $ k=\frac{YA}{l} $
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